The wavelength of the photon emitted when a hydrogen atom undergoes a transition from the n = 5 state to the n = 1 state is approximately
A)94.8 nm
B)0.109 nm
C)73.0 nm
D)90.0 nm
E)91.2 nm

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. The energy difference between the n = 5 and n = 1 states in a hydrogen atom is given by:E = -13.6 eV * (1/1^2 - 1/5^2) = -12.09 eVConverting this energy to joules and then using the equation E = hc/λ, we get:λ = hc/E = (6.626 x 10^-34 J s) * (3 x 10^8 m/s) / (-12.09 eV * 1.602 x 10^-19 J/eV) = 94.8 nmTherefore, the correct answer is A) 94.8 nm.

The Wavelength of the Photon Emitted When a Hydrogen Atom