In the Bohr model of the hydrogen atom, what is the kinetic energy of the electron in the n = 3 orbit? The radius of the first Bohr orbit is 0.0529 nm.)
A) 3.44 eV
B) 1.51 eV
C) 3.02 eV
D) 0.75 eV
E) 4.53 eV

Question

Quizplus · Accepted Answer

The kinetic energy of the electron in the nth orbit of a hydrogen atom can be found using the formula:

$E_k = \frac{-13.6	ext{ eV}}{n^2}$

For n = 3, the kinetic energy is:

$E_k = \frac{-13.6	ext{ eV}}{3^2} = -1.51	ext{ eV}$

Since kinetic energy cannot be negative, we take the absolute value:

$|E_k| = 1.51	ext{ eV}$

Therefore, the answer is B.

In the Bohr Model of the Hydrogen Atom, What Is