An electron accelerated from rest through an electrostatic potential difference of 750 kV would have a total energy of approximately
A) 1.261 MeV.
B) 0.750 MeV.
C) 0.511 MeV.
D) 0.239 MeV.
E) 0.038 MeV.

Question

Quizplus · Accepted Answer

The total energy of an electron accelerated through an electrostatic potential difference is given by the equation E = qV, where E is the total energy, q is the charge of the electron (1.6 x 10^-19 C), and V is the electrostatic potential difference. Plugging in the given values, we get:

E = (1.6 x 10^-19 C) x (750 x 10^3 V) = 1.2 x 10^-13 J

To convert this energy to MeV, we use the conversion factor 1 MeV = 1.6 x 10^-13 J. Thus:

E = (1.2 x 10^-13 J) / (1.6 x 10^-13 J/MeV) = 0.75 MeV

Therefore, the correct answer is A).

An Electron Accelerated from Rest Through an Electrostatic Potential Difference