Light is incident on a piece of glass in air at an angle of 37.0º from the normal.If the index of refraction of the glass is 1.50,the angle that the refracted ray makes with the normal is approximately
A)8.6º
B)21.8º
C)23.6º
D)41.8º
E)56.4º

Question

Quizplus · Accepted Answer

Using Snell's law,
$n_1\sin	heta_1=n_2\sin	heta_2$
$n_1$ is the refractive index of the medium from which the light is coming (air), which is approximately 1.
$n_2$ is the refractive index of the medium to which the light is entering (glass), which is given as 1.50.
$	heta_1$ is given as 37.0º.
Let $	heta_2$ be the angle that the refracted ray makes with the normal.
Then,
$	heta_2=\sin^{-1}\left(\dfrac{n_1}{n_2}\sin	heta_1ight)$
$	heta_2=\sin^{-1}\left(\dfrac{1}{1.50}\sin(37.0)ight)$
$	heta_2\approx 23.6º$
Therefore, the correct choice is (C).

Light Is Incident on a Piece of Glass in Air