Light of wavelength 500 nm illuminates parallel slits and produces an interference pattern on a screen that is 1 m from the slits. In terms of the initial intensity I₀, the light's intensity in the interference pattern at a point for which the path difference is 300 nm is A) 0.262 I₀. B) 0.382 I₀. C) 0.447 I₀. D) 0.581 I₀. E) 0.629 I₀.

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Quizplus · Accepted Answer

The intensity of the interference pattern at a point can be given by the equation: I = 4I_s cos^2 (πdΔ/λL) where I_s is the intensity of the individual slits, d is the distance between the slits, Δ is the path difference, λ is the wavelength of light, and L is the distance from the slits to the screen. We are given that the wavelength of light is 500 nm, the distance from the slits to the screen is 1 m, and the path difference is 300 nm. We can find the intensity by plugging in these values into the equation above and using the fact that cos^2 (πdΔ/λL) = cos^2 (π(0.0005)(0.3)/(1)) = 0.382. Therefore, the intensity of the interference pattern at the point with a path difference of 300 nm is 0.382 times the initial intensity, or 0.382 I₀..

Light of Wavelength 500 Nm Illuminates Parallel Slits and Produces