A 10-mH inductor has an internal resistance of 10 Ω. The impedance of this inductor for a frequency of 60 Hz is approximately
A) 3.77 Ω.
B) 10 Ω.
C) 13.8 Ω.
D) 10.6 Ω.
E) none of these is correct.

Question

Quizplus · Accepted Answer

The impedance of an inductor is calculated using the formula Z = √(R² + (ωL)²), where ω = 2πf. For a 10-mH inductor at 60 Hz, ω = 2π(60) = 377 rad/s. The inductive reactance XL = ωL = 377 * 0.01 = 3.77 Ω. The total impedance Z = √(10² + 3.77²) ≈ 13.8 Ω.

A 10-MH Inductor Has an Internal Resistance of 10 Ω