You connect a 250-Ω resistor, a 1.20-mH inductor, and a 1.80-μF capacitor in series across a 60.0-Hz, 120-V peak) source. The approximate impedance of your circuit is
A) 1.49 kΩ.
B) 1.47 kΩ.
C) 0.452 Ω.
D) 250 Ω.
E) none of these is correct.

Question

Quizplus · Accepted Answer

The impedance of the circuit can be calculated using the formula:
Z = √(R^2 + (XL - XC)^2)
where R = 250 Ω is the resistance, XL = ωL = 2πfL = 452.39 Ω is the inductive reactance, XC = 1/(ωC) = 88.24 Ω is the capacitive reactance, and f = 60 Hz is the frequency.
Plugging in the values, we get:
Z = √(250^2 + (452.39 - 88.24)^2)
Z ≈ 1.49 kΩ
Therefore, the closest option is (A) 1.49 kΩ.

You Connect a 250-Ω Resistor, a 1