A circular wire coil of radius 25 cm and 20 turns is sitting in a perpendicular magnetic field of 0.20 T. If the coil is rotated 90^o, what is the magnitude of the change in magnetic flux through the loop? A) 0 Wb B) 1.6 Wb C) 0.080 Wb D) 0.80 Wb E) 0.040 Wb

Question

Quizplus · Accepted Answer

The change in magnetic flux is calculated using the formula ΔΦ = B * A * N * cos(θ), where B is the magnetic field, A is the area of the coil, N is the number of turns, and θ is the angle of rotation. Initially, θ = 0° and finally θ = 90°. The area A = π * r² = π * (0.25 m)². The change in flux is B * A * N * (cos(0°) - cos(90°)) = 0.20 T * π * (0.25 m)² * 20 * (1 - 0) = 0.80 Wb.

A Circular Wire Coil of Radius 25 Cm and 20