An alpha particle with a charge of 2e e = 1.6 × 10^-19 C) is moving at right angles to a uniform magnetic field of 1.20 T. The radius of curvature of the track of the particle is 0.20 m. What is the momentum of the alpha particle?

Question

Quizplus · Accepted Answer

The momentum of a charged particle moving in a magnetic field is given by:p = qvBwhere:p is the momentum of the particleq is the charge of the particlev is the velocity of the particleB is the magnetic field strengthIn this problem, we are given:q = 2e = 3.2 × 10^-19 Cv = rω = (0.20 m)(1.20 T) = 2.40 × 10^6 m/sB = 1.20 TSubstituting these values into the equation above, we get:p = (3.2 × 10^-19 C)(2.40 × 10^6 m/s)(1.20 T) = 7.7 × 10^-20 kg m/sTherefore, the momentum of the alpha particle is 7.7 × 10^-20 kg m/s.

An Alpha Particle with a Charge of 2e E =