A 3.0-m long straight wire segment makes an angle of 28º with a uniform magnetic field of 1.0 T. The magnitude of the force on the wire if it carries a current of 1.5 A is approximately

Question

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = I * L * B * sin(θ). Substituting the given values: I = 1.5 A, L = 3.0 m, B = 1.0 T, and θ = 28º, we get F = 1.5 * 3.0 * 1.0 * sin(28º) ≈ 2.1 N.

A 30-M Long Straight Wire Segment Makes an Angle of 28º