5 T when a current of 1.3 A passes through the wire in a perpendicular direction to the magnetic field. Find the mass per unit length of the wire. The wire is connected to a battery by ultra light flexible leads.)

Question

Quizplus · Accepted Answer

The magnetic force on the wire is equal to the gravitational force acting on it. Using the formula F = BIL = mg, where B = 5 T, I = 1.3 A, and g = 9.8 m/s², we solve for m/L (mass per unit length): m/L = (BIL)/g = (5 * 1.3)/9.8 = 0.20 kg/m.

5 T When a Current of 1