A circular loop of wire of radius 6.0 cm has 30 turns and lies in the yz plane with its center at the origin. It carries a counterclockwise current of 5 A when viewed along the +x-axis. The magnetic field on the x-axis at x = 6.0 cm is approximately

Question

Quizplus · Accepted Answer

The magnetic field at a point along the x-axis due to a current loop is given by the equation:

$B_x = \frac{\mu_0 I a^2}{2(a^2+x^2)^{3/2}}$

where $a$ is the radius of the loop, $x$ is the distance from the center of the loop to the point on the x-axis, and $I$ is the current in the loop.

Plugging in the given values, we get:

$B_x = \frac{(4\pi 	imes 10^{-7} 	ext{ T m/A}) (5	ext{ A}) (0.06	ext{ m})^2}{2((0.06	ext{ m})^2+(0.06	ext{ m})^2)^{3/2}} = 0.56	ext{ mT}$

Therefore, the answer is B.

A Circular Loop of Wire of Radius 6