A wire of radius 0.35 cm carries a current of 75 A that is uniformly distributed over its cross-sectional area. The magnitude of the magnetic field B at a distance 0.20 cm from the center of the wire is approximately

Question

Quizplus · Accepted Answer

The magnetic field at a distance r from the center of a long straight wire carrying a current I is given by:B = (μ0 * I) / (2πr)where μ0 is the permeability of free space (4π × 10^-7 T·m/A).Plugging in the given values, we get:B = (4π × 10^-7 T·m/A * 75 A) / (2π * 0.20 cm) = 2.5 mTTherefore, the correct answer is A.

A Wire of Radius 0