If 4.7 × 10¹⁶ electrons pass a particular point in a wire every second, what is the current in the wire?

Question

Quizplus · Accepted Answer

To find the current, we need to use the formula: I = Q/t where I is the current in amperes, Q is the charge passing through the point in coulombs, and t is the time in seconds. We are given the number of electrons passing through the point in one second, which is: 4.7 × 10¹⁶ electrons/second To find the charge passing through the point in one second, we need to convert the number of electrons to coulombs. One electron has a charge of 1.6 × 10^-19 coulombs, so: (4.7 × 10¹⁶ electrons/second) × (1.6 × 10^-19 coulombs/electron) = 7.52 × 10^-12 coulombs/second Now we can plug this into the formula for current: I = Q/t = 7.52 × 10^-12 coulombs/second ÷ 1 second = 7.52 × 10^-12 amperes This is equivalent to 7.5 × 10^-3 mA, or 7.5 mA. Therefore, the answer is D.

If 47 × 1016 Electrons Pass a Particular Point in a a Wire

If 47 × 10¹⁶ Electrons Pass a Particular Point in a a Wire