In this circuit, two batteries, one with a potential difference of 10 V and the other with a potential difference of 20 V, are connected in series across a resistance of 90 Ω. The power delivered by the 10-V battery is approximately

Question

Quizplus · Accepted Answer

To find the power delivered by the 10-V battery, we need to first find the current flowing through the circuit. Using Ohm's Law, we can calculate the current as:

I = V/R = (10 V + 20 V)/90 Ω = 0.333 A

Now, the power delivered by the 10-V battery can be calculated as:

P = VI = (10 V)(0.333 A) = 3.33 W

However, this is an approximation since we have assumed that the internal resistances of the batteries are negligible. In reality, the batteries will have some internal resistance which would cause a voltage drop across them, leading to a slightly lower power output.

Therefore, the closest answer choice to 3.33 W is D) 3.3 W.

In This Circuit, Two Batteries, One with a Potential Difference