A metal sphere with a radius of 8.0 cm is used to accumulate charges until the electric field at the surface is 3.0 MV/m. How much charge can be accumulated on this sphere?

Question

Quizplus · Accepted Answer

The electric field E at the surface of a sphere is given by E = kQ/r^2, where k is Coulomb's constant (8.99 x 10^9 N m²/C²), Q is the charge, and r is the radius. Solving for Q gives Q = Er^2/k. Substituting E = 3.0 x 10^6 V/m, r = 0.08 m, and k = 8.99 x 10^9 N m²/C², we find Q ≈ 2.1 μC.

A Metal Sphere with a Radius of 8