A positive charge of 94.0 nC is 12.0 cm from a negative charge of 53.0 nC. The force on one of the charges due to the other is approximately

Question

Quizplus · Accepted Answer

We can use Coulomb's law to find the force between the charges:

$F = \frac{kq_1q_2}{r^2}$

where $k$ is the Coulomb constant ($8.99	imes10^9$ Nm$^2$/C$^2$), $q_1$ and $q_2$ are the charges, and $r$ is the distance between them.

Plugging in the values given in the problem, we get:

$F = \frac{(8.99	imes10^9)(94.0	imes10^{-9})(53.0	imes10^{-9})}{(0.12)^2} = 3.11	imes10^{-3}$ N

Converting to millinewtons (mN), we get:

$F = 3.11$ mN

Therefore, the best choice is C.

A Positive Charge of 94