Consider a uniform electric field E = 5.0 kN/C) parallel to the +x-axis. What is the flux of this field through a square of side 20 cm in a plane parallel to the yz plane?

Question

Quizplus · Accepted Answer

The electric flux through a surface is given by the formula Φ = E · A · cos(θ), where E is the electric field strength, A is the area of the surface, and θ is the angle between the field and the normal to the surface. Here, E = 5.0 kN/C, the side of the square is 0.20 m, so A = 0.20 m * 0.20 m = 0.04 m². Since the field is parallel to the +x-axis and the square is parallel to the yz plane, θ = 0°, and cos(0°) = 1. Thus, Φ = 5.0 kN/C * 0.04 m² * 1 = 0.20 kN·m²/C.

Consider a Uniform Electric Field E = 5