A cube of side 3.56 cm has a charge of 9.11 μC placed at its center. Calculate the electric flux through one side of the cube.

Question

Quizplus · Accepted Answer

We can use Gauss' law to find the electric flux through one side of the cube. Gauss' law states that the electric flux through a closed surface is proportional to the charge enclosed by the surface.

Since the cube has symmetry, we can use a cube with one face as our closed surface. The charge enclosed by this cube is simply the charge at the center, which is 9.11 μC.

The area of one face of the cube is (3.56 cm)^2 = 12.6736 cm^2 = 0.00126736 m^2.

Thus, the electric flux through one side of the cube is:

Φ = E x A = Q/ε0 x A

where ε0 is the permittivity of free space.

Φ = (9.11 × 10^-6 C) / (8.85 × 10^-12 N^-1 m^-2 C^2) x 0.00126736 m^2
Φ = 1.72 × 10^15 N m^2/C

Therefore, the answer is D.

A Cube of Side 3