A horizontal surface of area 0.321 m² has an electric flux of 123 N.m²/C passing through it at an angle of 25° to the horizontal. If the flux is due to a uniform electric field, calculate the magnitude of the latter.

Question

Quizplus · Accepted Answer

The electric flux through a surface is given by the product of the electric field strength and the area of the surface perpendicular to the field. In this case, the area perpendicular to the field is the area of the surface multiplied by the cosine of the angle between the field and the normal to the surface. Therefore, the electric field strength is given by:E = Φ/Acosθ = 123 N.m2/C / (0.321 m2cos25°) = 907 N m2/CTherefore, the correct answer is A.

A Horizontal Surface of Area 0