A large, flat conducting plate has a surface charge density σ = 8.0 × 10^-⁹C/m² on one of its surfaces. What is the magnitude of the electric field 10 µm from this plate?

Question

Quizplus · Accepted Answer

Using Gauss's Law, we know that the electric field due to a large, flat conducting plate is given by:
E = σ/2ε0

where σ is the surface charge density and ε0 is the permittivity of free space.

Plugging in the given values, we get:
E = (8.0 × 10^-11 C/m^2) / (2 × 8.85 × 10^-12 F/m)
E = 0.90 kN/C

Therefore, the magnitude of the electric field 10 µm from the plate is 0.90 kN/C.

A Large, Flat Conducting Plate Has a Surface Charge Density