During a certain thermodynamic process,418 J of work are done on a system and 214 cal of heat are transferred to the system.The change in internal energy during the process is
A)314 cal
B)114 cal
C)468 cal
D)368 cal
E)632 cal

Question

Quizplus · Accepted Answer

Explanation:Change in internal energy = Heat transferred to the system + Work done on the system= 214 cal + 418 J= 214 cal + (418 J * 0.239 cal/J)= 214 cal + 99.6 cal= 313.6 cal= 314 cal (rounded to the nearest whole number)

During a Certain Thermodynamic Process,418 J of Work Are Done