A car of mass 2000 kg is traveling at 22.0 m/s on a day when the temperature is 20.0^oC. The driver steps on the brakes and stops the car. By how much does the entropy of the universe increase?

Question

Quizplus · Accepted Answer

The correct answer is A.The change in entropy of the universe is given by the sum of the change in entropy of the car and the change in entropy of the environment. The change in entropy of the car is given by:$$\Delta S_{car} = - \int_{T_i}^{T_f} \frac{dQ}{T}$$where $T_i$ is the initial temperature of the car, $T_f$ is the final temperature of the car, and $dQ$ is the heat transferred from the car to the environment. The change in entropy of the environment is given by:$$\Delta S_{env} = \int_{T_i}^{T_f} \frac{dQ}{T}$$where $T_i$ is the initial temperature of the environment, $T_f$ is the final temperature of the environment, and $dQ$ is the heat transferred from the car to the environment. The change in entropy of the universe is given by:$$\Delta S_{universe} = \Delta S_{car} + \Delta S_{env} = - \int_{T_i}^{T_f} \frac{dQ}{T} + \int_{T_i}^{T_f} \frac{dQ}{T} = 0$$Therefore, the change in entropy of the universe is zero.

A Car of Mass 2000 Kg Is Traveling at 22