A volume of an ideal gas goes through a temperature change from 20^oC to 60^oC. The relation between the average molecular kinetic energy at 20^oC K₁) and that at 60^oC K₂) is

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According to the kinetic theory of gases, the average molecular kinetic energy of a gas is directly proportional to its temperature in Kelvin. Therefore, the ratio of the average molecular kinetic energy at 60^oC to that at 20^oC is equal to the ratio of the absolute temperatures: K₂ / K₁ = (273 + 60) / (273 + 20) = 333 / 293 ≈ 1.14 Therefore, the answer is D: K₁ = 0.88 K₂.

A Volume of an Ideal Gas Goes Through a Temperature