75 × 10^-10 m, the mean free path of the O₂ molecule is

Question

Quizplus · Accepted Answer

The mean free path of a molecule is given by the formula:λ = (kT)/(√2πd²P)where:k is the Boltzmann constant (1.38 × 10^-23 J/K)T is the temperature (in Kelvin)d is the diameter of the molecule (in meters)P is the pressure (in Pascals)In this problem, we are given the following information:d = 75 × 10^-10 mT = 298 KP = 1 atm = 101325 PaPlugging these values into the formula, we get:λ = (1.38 × 10^-23 J/K)(298 K)/(√2π(75 × 10^-10 m)²(101325 Pa))= 6.53 × 10^-8 mTherefore, the mean free path of the O2 molecule is 6.53 × 10^-8 m, which corresponds to choice A.

75 × 10-10 M, the Mean Free Path of the O2

75 × 10^-10 M, the Mean Free Path of the O₂