A lake with 8.0 × 10⁹ kg of water, which has a specific heat of 4180 J/kg · C^o, warms from 10^oC to 15^oC. The amount of heat transferred to the lake is

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The amount of heat transferred to the lake is given by the equation:Q = mcΔTwhere:Q is the amount of heat transferred (in joules)m is the mass of the water (in kilograms)c is the specific heat of water (in joules per kilogram per degree Celsius)ΔT is the change in temperature (in degrees Celsius)In this case, we have:m = 8.0 × 10^9 kgc = 4180 J/kg · C^oΔT = 15^o - 10^o = 5^oSubstituting these values into the equation, we get:Q = (8.0 × 10^9 kg)(4180 J/kg · C^o)(5^o) = 1.7 × 10^14 JTherefore, the correct answer is B) 1.7 × 10^14 J.

A Lake with 8