Glass beads of mass 100 g and specific heat 0.20 cal/g · C^o are heated to 90^oC and placed in a 300-g glass beaker containing 200 g of water at 20^oC. When equilibrium is reached, the temperature is approximately

Question

Quizplus · Accepted Answer

The heat lost by the beads equals the heat gained by the water and beaker. Using the formula $m \cdot c \cdot \Delta T$ for each component and solving for the final temperature, the equilibrium temperature is approximately 25°C.

Glass Beads of Mass 100 G and Specific Heat 0