If the heat given off by 300 g of an alloy as it cools through 50 C^o is sufficient to raise the temperature of 300 g of water from 30^o to 40^oC, the specific heat of the alloy must be approximately

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Quizplus · Accepted Answer

The heat lost by the alloy is equal to the heat gained by the water. Using the formula $ Q = mc\Delta T $, where $ m $ is mass, $ c $ is specific heat, and $ \Delta T $ is the change in temperature, we set up the equation: $ 300 \times c \times 50 = 300 \times 1 \times 10 $. Solving for $ c $, we get $ c = 0.20 $ cal/g°C.

If the Heat Given Off by 300 G of an Alloy