For a tube of length 57.0 cm that is open at both ends, what is the frequency of the fundamental mode? The speed of sound in air is 340 m/s.)
A) 149 Hz
B) 447 Hz
C) 596 Hz
D) 298 Hz
E) 746 Hz

Question

Quizplus · Accepted Answer

The fundamental frequency for a tube open at both ends is given by the formula f = v / (2L), where v is the speed of sound and L is the length of the tube. Substituting the given values, f = 340 m/s / (2 * 0.57 m) = 298.25 Hz, which rounds to 298 Hz.

For a Tube of Length 57