A 2.00-kg body is attached to a spring of negligible mass and oscillates with a period of 1.00 s. The force constant of the spring is

Question

Quizplus · Accepted Answer

The period of a mass-spring system is given by:

$T = 2\pi\sqrt{\frac{m}{k}}$

Where $m$ is the mass and $k$ is the force constant of the spring.

Plugging in the given values:

$1.00 	ext{ s} = 2\pi\sqrt{\frac{2.00 	ext{ kg}}{k}}$

Solving for $k$:

$k = \frac{(2\pi)^2 \cdot 2.00 	ext{ kg}}{(1.00 	ext{ s})^2} = 79.0 	ext{ N/m}$

Therefore, the correct choice is E.

A 200-Kg Body Is Attached to a Spring of Negligible Mass