The acceleration of a particle moving with simple harmonic motion is given by a = -16.0 x, where x is in meters and a is in meters per second squared. The period of the motion is
A) 0.250 s
B) 0.392 s
C) 1.57 s
D) 4.00 s
E) 25.2 s

Question

Quizplus · Accepted Answer

The acceleration of a particle in simple harmonic motion is given by a = -ω^2x, where ω is the angular frequency in radians per second. Comparing this with the given equation a = -16.0x, we can see that ω^2 = 16.0, or ω = 4.0 (radians per second).
The period of simple harmonic motion is given by T = (2π/ω). Substituting ω = 4.0, we get T = (2π/4.0) = 1.57 seconds. 
Therefore, the answer is C) 1.57 s.

The Acceleration of a Particle Moving with Simple Harmonic Motion