Two pistons of a hydraulic lift have radii of 2.67 cm and 20.0 cm, respectively. The downward force on the 2.67-cm piston that is required to lift a mass of 2000 kg supported by the 20-cm piston is

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The force required to lift the mass is equal to the weight of the mass, which is 2000 kg * 9.8 m/s^2 = 19600 N. The area of the smaller piston is pi * (2.67 cm)^2 = 22.4 cm^2, and the area of the larger piston is pi * (20.0 cm)^2 = 1256 cm^2. The pressure on the smaller piston is therefore 19600 N / 22.4 cm^2 = 875 N/cm^2. The force on the smaller piston is therefore 875 N/cm^2 * 22.4 cm^2 = 19600 N, which is equal to the weight of the mass.

Two Pistons of a Hydraulic Lift Have Radii of 2