A 3.00-m long wire with a diameter of 1.50 mm has Young's modulus of 9.00 x10¹⁰ N/m². What mass has to be attached to the wire so that it would extend it by 3.00 mm under its weight?

Question

Quizplus · Accepted Answer

To find the mass, use the formula for extension: ΔL = (F*L) / (A*Y), where F = mg, L = original length, A = cross-sectional area, Y = Young's modulus. Solving for m gives m = (ΔL * A * Y) / (g * L). Substituting the given values, m = (3.00 mm * π * (0.75 mm)^2 * 9.00 x 10^10 N/m^2) / (9.81 m/s^2 * 3.00 m), which results in approximately 16.2 kg.

A 300-M Long Wire with a Diameter of 1