A uniform disk I_o = ½ mR²) of mass m and radius R is suspended from a point on its rim. The moment of inertia of the disk about an axis perpendicular to the disk through the pivot point is A) ½ mR². B) mR². C) 1.5mR². D) 2mR². E) 2mR²/3.

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Quizplus · Accepted Answer

Using the parallel axis theorem, the moment of inertia about the pivot point is I = I_o + md² = ½ mR² + mR² = 1.5mR².

A Uniform Disk Io = ½ MR2) of Mass M

A Uniform Disk I_o = ½ MR²) of Mass M