A block is placed on an inclined plane with an angle of inclination $\theta$ in degrees) with respect to horizontal. The coefficient of static friction between the block and the inclined plane is 0.7. For what maximum value of $\theta$ will the block remain stationary on the inclined surface? A) 35^o B) 82^o C) 44^o D) 30^o E) 18^o

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Quizplus · Accepted Answer

The maximum value of $\theta$ for which the block will remain stationary on the inclined surface is given by:$$\theta = \tan^{-1}(\mu_s)$$where $\mu_s$ is the coefficient of static friction.In this case, $\mu_s$ = 0.7, so:$$\theta = \tan^{-1}(0.7) = 35^o$$

A Block Is Placed on an Inclined Plane with an Angle