A block of mass m is suspended by two strings and is in equilibrium as suggested in the figure above. The tension of the right-hand string divided by the tension of the left-hand string is given by A) sin $\theta$₂ / sin $\theta$₁. B) cos$\theta$₁ / cos $\theta$₂. C) cos $\theta$₂/ cos $\theta$₁. D) sin $\theta$₁ / sin $\theta$₂. E) mg $\theta$T₁ sin $\theta$₁) / T₁ sin $\theta$₂).

Question

Quizplus · Accepted Answer

The Answer of A block of mass m is suspended by two strings and is in equilibrium as suggested in the figure above. The tension of the right-hand string divided by the tension of the left-hand string is given by A) sin $\theta$₂ / sin $\theta$₁. B) cos$\theta$₁ / cos $\theta$₂. C) cos $\theta$₂/ cos $\theta$₁. D) sin $\theta$₁ / sin $\theta$₂. E) mg $\theta$T₁ sin $\theta$₁) / T₁ sin $\theta$₂).

A Block of Mass M Is Suspended by Two Strings θ\thetaθ

A Block of Mass M Is Suspended by Two Strings $\theta$