A projectile is ejected from a 25-m high tower with a velocity of 40 m/s at an angle of 30 degrees to the horizontal first on Earth and then on Mars.What is the ratio of the time taken to hit the ground on Mars compared to Earth? (Assume g_Mars = 0.38g_Earth) A)2.4 B)2.6 C)0.38 D)6.9 E)1.0

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The time taken for a projectile to hit the ground can be found using the equation: h = utsinθ - 1/2gt^2 where h is the initial height, u is the initial velocity, θ is the angle of projection, g is the acceleration due to gravity, and t is the time taken to hit the ground. On Earth: h = 25 m u = 40 m/s θ = 30° g = 9.8 m/s^2 (approx.) Plugging in these values, we get: 25 = 40sin30°t - 1/2(9.8)t^2 Simplifying and solving for t, we get: t = 2.05 s On Mars: g = 0.38g_Earth = 0.38(9.8) = 3.724 m/s^2 (approx.) Plugging in the same values and using the new value of g, we get: 25 = 40sin30°t - 1/2(3.724)t^2 Simplifying and solving for t, we get: t = 5.01 s The ratio of the time taken on Mars compared to Earth is: 5.01 s / 2.05 s ≈ 2.44 ≈ 2.4

A Projectile Is Ejected from a 25-M High Tower with a Velocity