Consider an event X comprised of three outcomes whose probabilities are $ \frac{9}{18}, \frac{1}{18} $, and $ \frac{6}{18} $ Compute the probability of the complement of the event.

A) $ \frac{2}{18} $

B) $ \frac{1}{2} $

C) $ \frac{16}{3} $

D) $ \frac{16}{18} $

Question

Consider an event X comprised of three outcomes whose probabilities are $ \frac{9}{18}, \frac{1}{18} $, and $ \frac{6}{18} $ Compute the probability of the complement of the event.

A) $ \frac{2}{18} $

B) $ \frac{1}{2} $

C) $ \frac{16}{3} $

D) $ \frac{16}{18} $

Quizplus · Accepted Answer

The probability of event X is the sum of its outcomes: $ \frac{9}{18} + \frac{1}{18} + \frac{6}{18} = \frac{16}{18} $. The probability of the complement is $ 1 - \frac{16}{18} = \frac{2}{18} $.

Consider an Event X Comprised of Three Outcomes Whose Probabilities 918,118 \frac{9}{18}, \frac{1}{18} 189​,181​

Consider an Event X Comprised of Three Outcomes Whose Probabilities $\frac{9}{18}, \frac{1}{18}$