A scuba diver dives down to 15 m, where the pressure is 2.5 atm.The scuba diver then inhales 500.mL of air and holds his breath while ascending to the water surface, where the pressure is 1 atm.What is the volume of the air in the diver's lungs at the surface? Assume that T and n are constant.
A) 0.0050 mL
B) 0.20 mL
C) 5.0 mL
D) 200 mL
E) 1,250 mL

Question

Quizplus · Accepted Answer

Using Boyle's Law (P1V1 = P2V2), where P1 = 2.5 atm, V1 = 500 mL, and P2 = 1 atm, we can solve for V2 (the volume at the surface). V2 = (P1V1)/P2 = (2.5 atm * 500 mL) / 1 atm = 1250 mL.

A Scuba Diver Dives Down to 15 M, Where the Pressure