If the results of a one-factor within-subjects analysis of variance were summarized as F(2, 28) = 2.79, p .05, then you know that the experiment used subjects and the differences between the treatment condition means were .
A)15; nonsignificant
B)15; statistically significant
C)29; statistically significant
D)29; nonsignificant

Question

If the results of a one-factor within-subjects analysis of variance were summarized as F(2, 28) = 2.79, p > .05, then you know that the experiment used subjects and the differences between the treatment condition means were .
A)15; nonsignificant
B)15; statistically significant
C)29; statistically significant
D)29; nonsignificant

Quizplus · Accepted Answer

The degrees of freedom between groups is 2, indicating 3 levels of the factor (since degrees of freedom are calculated as the number of levels minus 1). The degrees of freedom within subjects is 28, which, for a within-subjects design, suggests there were 15 subjects (since degrees of freedom within are calculated as the product of the degrees of freedom between and the number of subjects minus 1, thus 2*(n-1) = 28, solving for n gives 15). The p-value being greater than .05 indicates the results were not statistically significant.

If the Results of a One-Factor Within-Subjects Analysis of Variance