For a sample of 25 observations taken from a normally distributed population with standard deviation of 6, a 95% confidence interval estimate for the population mean would require the use of: $\begin{array}{|l|l|}
\hline A&\text {t=2.064 }\
\hline B&\text {t=1.711 }\
\hline C&X^{2}=39.3641\
\hline D&\text { z=1.96}\
\hline
\end{array}$

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The Answer of For a sample of 25 observations taken from a normally distributed population with standard deviation of 6, a 95% confidence interval estimate for the population mean would require the use of: $\begin{array}{|l|l|}
\hline A&\text {t=2.064 }\
\hline B&\text {t=1.711 }\
\hline C&X^{2}=39.3641\
\hline D&\text { z=1.96}\
\hline
\end{array}$

For a Sample of 25 Observations Taken from a Normally At=2.064 Bt=1.711 CX2=39.3641D z=1.96\begin{array}{|l|l|}\hline A&\text {t=2.064 }\\\hline B&\text {t=1.711 }\\\hline C&X^{2}=39.3641\\\hline D&\text { z=1.96}\\\hline\end{array}ABCD​t=2.064 t=1.711 X2=39.3641 z=1.96​​

For a Sample of 25 Observations Taken from a Normally $\begin{array}{|l|l|}\hline A&\text {t=2.064 }\\\hline B&\text {t=1.711 }\\\hline C&X^{2}=39.3641\\\hline D&\text { z=1.96}\\\hline\end{array}$