In developing an interval estimate for a population mean, the population standard deviation $\sigma$was assumed to be 10. The interval estimate was 50.92 ± 2.14. Had $\sigma$equaled 20, the interval estimate would have been: $\begin{array}{|l|l|}
\hline \text { A. } & 60.92 \pm 2.14 . \
\hline \text { B. } & 50.92 \pm 12.14 \
\hline \text { C. } & 101.84 \pm 4.28 \
\hline \text { D. } & 50.92 \pm 4.28 . \
\hline
\end{array}$

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The Answer of In developing an interval estimate for a population mean, the population standard deviation $\sigma$was assumed to be 10. The interval estimate was 50.92 ± 2.14. Had $\sigma$equaled 20, the interval estimate would have been: $\begin{array}{|l|l|}
\hline \text { A. } & 60.92 \pm 2.14 . \
\hline \text { B. } & 50.92 \pm 12.14 \
\hline \text { C. } & 101.84 \pm 4.28 \
\hline \text { D. } & 50.92 \pm 4.28 . \
\hline
\end{array}$

In Developing an Interval Estimate for a Population Mean, the Population