The expected value, E(X), of a binomial probability distribution is: $\begin{array}{|l|l|}
\hline A&n+p \
\hline B&n p(1-p)\
\hline C&n p\
\hline D&n+p-1\
\hline
\end{array}$

Question

The expected value, E(X), of a binomial probability distribution is: $\begin{array}{|l|l|}
\hline  A&n+p \
\hline  B&n p(1-p)\
\hline  C&n p\
\hline  D&n+p-1\
\hline 
\end{array}$

Quizplus · Accepted Answer

The Answer of The expected value, E(X), of a binomial probability distribution is: $\begin{array}{|l|l|}
\hline  A&n+p \
\hline  B&n p(1-p)\
\hline  C&n p\
\hline  D&n+p-1\
\hline 
\end{array}$

The Expected Value, E(X), of a Binomial Probability Distribution Is An+pBnp(1−p)CnpDn+p−1\begin{array}{|l|l|}\hline A&n+p \\\hline B&n p(1-p)\\\hline C&n p\\\hline D&n+p-1\\\hline \end{array}ABCD​n+pnp(1−p)npn+p−1​​

The Expected Value, E(X), of a Binomial Probability Distribution Is $\begin{array}{|l|l|}\hline A&n+p \\\hline B&n p(1-p)\\\hline C&n p\\\hline D&n+p-1\\\hline \end{array}$