Let X represent the number of computers in Australian households who own computers. The probability distribution of X is as follows: $$\begin{array} { c | c c c c c }
x & 1 & 2 & 3 & 4 & 5 \
\hline p ( x ) & .25 & .33 & .17 & .15 & .10
\end{array}$$ What is the probability that a randomly selected Australian household will have:
a. more than 2 computers?
b. between 2 and 5 computers, inclusive?
c. fewer than 3 computers?

Question

Let X represent the number of computers in Australian households who own computers. The probability distribution of X is as follows: $$\begin{array} { c | c c c c c } 
x & 1 & 2 & 3 & 4 & 5 \
\hline p ( x ) & .25 & .33 & .17 & .15 & .10
\end{array}$$ What is the probability that a randomly selected Australian household will have:
a. more than 2 computers?
b. between 2 and 5 computers, inclusive?
c. fewer than 3 computers?

Quizplus · Accepted Answer

The Answer of Let X represent the number of computers in Australian households who own computers. The probability distribution of X is as follows: $$\begin{array} { c | c c c c c } 
x & 1 & 2 & 3 & 4 & 5 \
\hline p ( x ) & .25 & .33 & .17 & .15 & .10
\end{array}$$ What is the probability that a randomly selected Australian household will have:
a. more than 2 computers?
b. between 2 and 5 computers, inclusive?
c. fewer than 3 computers?

Let X Represent the Number of Computers in Australian Households x12345p(x).25.33.17.15.10\begin{array} { c | c c c c c } x & 1 & 2 & 3 & 4 & 5 \\\hline p ( x ) & .25 & .33 & .17 & .15 & .10\end{array}xp(x)​1.25​2.33​3.17​4.15​5.10​​

Let X Represent the Number of Computers in Australian Households $\begin{array} { c | c c c c c } x & 1 & 2 & 3 & 4 & 5 \\\hline p ( x ) & .25 & .33 & .17 & .15 & .10\end{array}$