Ethylene glycol, used as a coolant in automotive engines, has a specific heat capacity of 2.42 J/(g-K). Calculate q when 3.65 kg of ethylene glycol is cooled from 132$\degree$C to 85$\degree$C.

Question

Quizplus · Accepted Answer

The heat transfer (q) can be calculated using the formula q = mcΔT, where m is mass, c is specific heat capacity, and ΔT is the change in temperature. Converting 3.65 kg to grams gives 3650 g. ΔT = 85 - 132 = -47°C. Thus, q = 3650 g * 2.42 J/(g-K) * (-47 K) = -416,829 J = -416.829 kJ, which is approximately -420 kJ.

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