Linolenic acid (C₁₈H₃₀O₂) can be hydrogenated to stearic acid by reacting it with hydrogen gas according to the equation: C₁₈H₃₀O₂ + 3H₂ $\to$ C₁₈H₃₆O₂
What volume of hydrogen gas, measured at STP, is required to react with 10.5 g of linolenic acid in this reaction?

Question

Linolenic acid (C₁₈H₃₀O₂) can be hydrogenated to stearic acid by reacting it with hydrogen gas according to the equation: C₁₈H₃₀O₂ + 3H₂

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C₁₈H₃₆O₂
What volume of hydrogen gas, measured at STP, is required to react with 10.5 g of linolenic acid in this reaction?

Quizplus · Accepted Answer

The molar mass of linolenic acid (C18H30O2) is approximately 278 g/mol. Therefore, 10.5 g of linolenic acid is 10.5 g / 278 g/mol = 0.0378 mol. According to the reaction, 3 moles of H2 are required per mole of linolenic acid, so 0.0378 mol * 3 = 0.1134 mol of H2 is needed. At STP, 1 mole of gas occupies 22.4 L, so 0.1134 mol * 22.4 L/mol = 2.54 L, which is approximately 2.53 L.

Linolenic Acid (C18H30O2) Can Be Hydrogenated to Stearic Acid by Reacting

Linolenic Acid (C₁₈H₃₀O₂) Can Be Hydrogenated to Stearic Acid by Reacting