Hydrochloric acid is prepared by bubbling hydrogen chloride gas through water. What is the concentration of a solution prepared by dissolving 225 L of HCl(g) at 37$\degree$C and 89.6 kPa in 5.25 L of water?

Question

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The correct answer is A because the concentration of the solution is 1.49 M. This can be calculated using the ideal gas law, which states that PV = nRT. In this case, P = 89.6 kPa, V = 225 L, n is the number of moles of HCl gas, R is the ideal gas constant (8.314 J/mol*K), and T = 37$\degree$C + 273.15 = 310.15 K. Solving for n, we get n = PV/RT = (89.6 kPa * 225 L) / (8.314 J/mol*K * 310.15 K) = 8.05 mol. The concentration of the solution is then calculated as n/V = 8.05 mol / 5.25 L = 1.49 M.

Hydrochloric Acid Is Prepared by Bubbling Hydrogen Chloride Gas Through °\degree°

Hydrochloric Acid Is Prepared by Bubbling Hydrogen Chloride Gas Through $\degree$