How many moles of H⁺(aq) ions are present in 1.25 L of 0.75 M nitric acid?

Question

Quizplus · Accepted Answer

The balanced chemical equation for nitric acid (HNO3) is:
HNO3 + H2O → H3O+ + NO3-
Therefore, in 1.25 L of 0.75 M nitric acid, the concentration of H3O+ ions (i.e. HS1U1P1+) is also 0.75 M. 
Thus, the number of moles of HS1U1P1+ ions present in 1.25 L of nitric acid is:
moles = concentration x volume = 0.75 M x 1.25 L = 0.94 mol
The concentration of NO3- ions (i.e. S1S1P0) is also 0.75 M, but since the question only asks for the number of moles of HS1U1P1+S1S1P0(aq) ions, we don't need to consider it in this calculation. Therefore, the correct answer is C) 0.94 mol.

How Many Moles of H+(aq) Ions Are Present in 1

How Many Moles of H⁺(aq) Ions Are Present in 1