Calculate$\Delta$S$\degree$ for the combustion of propane.

Question

Quizplus · Accepted Answer

The given equation for the combustion of propane is:
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l)
Let's first calculate the standard enthalpy of formation (∆Hf) for propane:
∆Hf(C3H8) = -104.67 kJ/mol
Next, we can calculate the standard enthalpy of combustion (∆Hc) for propane using the enthalpies of formation of the reactants and products:
∆Hc = 3∆Hf(CO2) + 4∆Hf(H2O) - ∆Hf(C3H8) - 5∆Hf(O2)
Plugging in the values, we get:
∆Hc = -2043.45 kJ/mol
Now, we can use the following equation to calculate the standard entropy of combustion (∆Sc) for propane:
∆Sc = ∆Hc/T
Plugging in the values, we get:
∆Sc = -100.9 J/K
Therefore, the correct answer is D) -100.9 J/K.

Calculate Δ\DeltaΔ S °\degree° For the Combustion of Propane

Calculate $\Delta$ S $\degree$ For the Combustion of Propane