A chemical reaction has $\Delta$H$\degree$ = 42.8 kJ and $\Delta$S$\degree$ = 92.5 J/K, at 25$\degree$ C. Calculate the temperature at which $\Delta$G$\degree$ = 0. State any approximation involved in your calculation.

Question

A chemical reaction has $\Delta$H$\degree$  = 42.8 kJ and $\Delta$S$\degree$  = 92.5 J/K, at 25$\degree$ C. Calculate the temperature at which $\Delta$G$\degree$ = 0. State any approximation involved in your calculation.

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The Answer of A chemical reaction has $\Delta$H$\degree$  = 42.8 kJ and $\Delta$S$\degree$  = 92.5 J/K, at 25$\degree$ C. Calculate the temperature at which $\Delta$G$\degree$ = 0. State any approximation involved in your calculation.

A Chemical Reaction Has Δ\DeltaΔ H °\degree° = 428 KJ And Has Δ\DeltaΔ

A Chemical Reaction Has $\Delta$ H $\degree$ = 428 KJ And Has $\Delta$